# What is the magnitude of the electric field at the midpoint between two protons?

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## Top best answers to the question «What is the magnitude of the electric field at the midpoint between two protons»

Answer and Explanation: The electric field due to two protons at their mid point will be zero, since individual electric field due to each proton is equal and opposite to...

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Those who are looking for an answer to the question «What is the magnitude of the electric field at the midpoint between two protons?» often ask the following questions:

### 👉 What is the relationship between electric field magnitude and electric field length?

- The magnitude
**of**the**electric field**is proportional**to**the length**of**E. If a test charge which is relatively larger is brought within the area of the source charge Q it is bound**to**modify the original electric field due**to**source charge. A simple way to escape from this conflict is**to use**a very negligible test charge q.

- What is magnitude of electric field?
- How to find magnitude of electric field between two charges?
- Is electric field magnitude constant?

### 👉 What is the average electric field at the midpoint?

Two point charges q A = 3 μC and q B = −3 μC are located 20 cm apart in vacuum. (a) What is the electric field at the midpoint O of the line AB joining the two charges? (b) If a negative test charge of magnitude 1.5 × 10 −9 C is placed at this point, what is the force experienced by the test charge?

- What is the magnitude of the electric field between two metal plates?
- What determines magnitude of electric field graph?
- How to calculate electric field magnitude?

### 👉 How to find magnitude of electric field between plates?

The magnitude of Electric Field. One way to generate a uniform electric field is to place two plates close to each other, then give one of them a positive charge and the other an equal negative charge. This will create an electric field between the plates that is directed away from the positively charged plate and towards the negatively charged plate.

- How to find electric field magnitude?
- How do protons behave in an electric field?
- Does electric field magnitude increase with distance?

We've handpicked 20 related questions for you, similar to «What is the magnitude of the electric field at the midpoint between two protons?» so you can surely find the answer!

What is the magnitude electric field at a distance?The magnitude of the net electric field at a distance x from the center and on the axis of a uniformly charged ring of radius r and total charge q is given by Enet = kqx. . Consider two identical rings of radius 12.0 cm each, located as shown in the diagram below. The charge per unit length on each ring is +3.90 nC/cm and d = 26.0 cm.

What is the magnitude of the uniform electric field?The magnitude of the force on a charge in an electric field is obtained from the equation **F = qE**. F = (0.500 × 10^{−}^{6} C)(6.25 × 10^{5} V/m) = 0.313 N.

- Furthermore, protons and electrons are responsible for
**the**development of**electric**fields, which apply a force termed as Coulomb force. This force is known to be outward radiating in all directions.

According to our assumption, the positively charged particle feels a force in the direction of the electric field. The acceleration of a particle between the plates is proportional to the magnitude of the electric field. A positively charged particle moves toward the negative plate, a negatively charged toward the positive. FAQ

How do you calculate magnitude of electric field?- Electric field equation. You can estimate the electric field created by a point charge with below electric field equation:
**E = k * Q / r²**. where. E is the magnitude of electric field, Q is the charge point, r is the distance from the point, k is the Coulomb's constant k = 1/(4 * π * ɛ0) = 8.9876 * 10^9 N * m² / C².

The electric field E is defined to be E=Fq E = F q , where F is the Coulomb or electrostatic force exerted on a small positive test charge q. E has units of N/C. The magnitude of the electric field E created by a point charge Q is **E=k|Q|r2 E = k | Q | r 2** , where r is the distance from Q.

#### What is the formula for electric field strength?

- The formula for calculating electric field strength is
**E=F/q**and where F is Force experienced

more. Maybe it would be more clear if the magnitude of the electric field was said to be equal to k times the absolute value of the charge creating the field divided by the distance squared. This would eliminate the discussion about whether or not to include the sign in the computation.

Is electric field dependent of magnitude of charge?Electric field is dependent on the magnitude of the electric charge, E = qzc/r2

- The magnitude and the direction of the electric field can be determined by the
**Coulomb force F on the test charge q**. If the field is created by a positive charge, the electric field will be in radially outward direction and if the field is created by negative charge, the electric field will be in radially inwards direction.

- The magnitude or strength of an
**electric field**in the space surrounding a source**charge is**related directly to the quantity of**charge**on the source charge and inversely to the distance from the source charge.

The magnitude of the **electric field** around an electric charge, considered as source of the **electric field**, **depends on** how the charge is distributed in space… The value of the electric field has dimensions of force per unit charge.

The moving electric charge causes an increase in the electric field in front of it and a decrease in the electric field in back of it, and these changes create a magnetic field, but let's go back to the charge. Let's imagine that this charge is moving extremely fast, at relativistic speeds even.

Can the magnitude of an electric field be negative?- Electric field can never "be negative.". Electric field is a vector it has magnitude and direction. Sometimes in a 1-dimensional problem, by convention physicists choose one direction to be positive, one negative.

- The magnitude of the electric field is given by the formula
**E = F/q**, where E is the strength of the electric field, F is the electric force, and q is the test charge that is being used to “feel” the electric field. For two point charges, F is given by Coulomb ’s law above.

- Enter the total charge and distance to calculate the electric field at that specific distance. This calculator evaluates the magnitude of an electric field at a given distance. The formula used to calculate the magnitude of an electric field at a given distance is as follows: k is Coulomb’s constant which is equal to 8.9876 * 10^9 N * m² / C²

- Points charge create an
**electric field**that gets smaller and smaller as one goes farther away from the source. The mathematical description of this**is**E = k Q/r^2. The k**is**just a**constant**that you can look up in a book and Q**is**the**magnitude**the source charge and r is the distance between the source and the target.

- The magnitude of the electric force felt by the proton placed in a uniform electric field of
**2800 N/C=charge of proyon *electric field the magnitude of the electric force =1.6*10^-19*2900**a) The magnitude of the electric force = 4.64 *10^-16 N

Magnitude of electric field Formula. Thus, the magnitude of electric field due to a point charge is given by relation $E=\frac{F}{q’} =\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}$ It is important to note here that the magnitude of $\vec E$ depends on the charge $q$ wgich produces the electric field not on the value of test charge $q’$.

How to find the magnitude of radiative electric field?The solution for the electric potential Φ due to charge q at some position rq other than the origin follows from (10.1.10): Φ () r =q ( 4πε o r −r q ) =q ( 4πε o r pq ) ] V [ (10.1.11)