# Are electric field lines perpendicular to field lines?

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Date created: Fri, Jul 23, 2021 4:43 AM
Date updated: Sun, Jun 26, 2022 9:11 AM

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Video answer: Why are electric field lines perpendicular to the .

## Top best answers to the question Â«Are electric field lines perpendicular to field linesÂ»

• Properties of Electric Field Lines The field lines never intersect each other. The field lines are perpendicular to the surface of the charge.

Video answer: Why are electric field lines perpendicular at a point .

Since the electric field lines point radially away from the charge, they are perpendicular to the equipotential lines. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Click to see full answer.

Following are the basic properties of electric field lines: Field lines start from a positive charge and end on a negative charge. Electric field lines move away from the positive electric charge and towards the negative electric charge. A tangent drawn at any point on a field line gives the electric field direction at that point.

Thus if you find this locus it is always perpendicular because of the fact that electric field lines actually represent the gradient in potential.

Properties of Electric Field Lines The field lines never intersect each other. The field lines are perpendicular to the surface of the charge. The magnitude of charge and the number of field lines, both are proportional to each other.

Consider an equipotential surface with electric field lines that are not perpendicular to the surface. These field lines could then be resolved into two components, one perpendicular to the surface and one along the surface. The field line along the surface means that the charges would move along the surface in the direction of the field lines.

Electric Field lines are perpendicular to the surface of any conductor because of vector addition of the fields.... If theElectric Field had components parallel to the surface of a conductor, free charges on the surface would move, contradicting electrostatic equilibrium.

Now, suppose electric field lines are not perpendicular to the local surface of the conductor. Then electric field will have some component parallel to the surface. This component will give potential difference dV=-E (parallel).dl between the nearby points. Then, the surface is not equipotential surface.